unspecified minpoly
shengyushen · Fri Feb 06, 2015 11:11 am
Dear all:
I am learning using singular , and I run the following script in singular
> ring A1=(2^3,a),x,dp;
> minpoly ;
1*a^3+1*a^1+1*a^0
> ring A2=(2,a),x,dp;
// ** redefining A2 **
> minpoly ;
0
I am confused by it,
I have not specified a monopoly for both A1 and A2 rings, but the A1 have a monopoly already, but not the A2.
Does this means that the A1 have only 1 monopoly so we don't need to specify it?
Shengyu Shen
I am learning using singular , and I run the following script in singular
> ring A1=(2^3,a),x,dp;
> minpoly ;
1*a^3+1*a^1+1*a^0
> ring A2=(2,a),x,dp;
// ** redefining A2 **
> minpoly ;
0
I am confused by it,
I have not specified a monopoly for both A1 and A2 rings, but the A1 have a monopoly already, but not the A2.
Does this means that the A1 have only 1 monopoly so we don't need to specify it?
Shengyu Shen